java程序执行超时

public class MethodTest {
	/**
	 * 要测试的方法
	 * @return
	 */
	public String test() {
		try {
			Thread.sleep(5);
		} catch (InterruptedException e) {
			e.printStackTrace();
		}
		return "test";
	}
}

 

public static void main(String[] args) {
		MethodTest test = new MethodTest();
		Callable<String> call = getCallable("test", test, (Object[])null);
		
		String result = testFuture(call, 1, TimeUnit.MILLISECONDS);
		System.out.println(result);
	}
	
	/**
	 * 
	 * @param <T>
	 * @param methodName 要执行的方法名
	 * @param obj	方法所在的对象
	 * @param args	方法的参数
	 * @return
	 */
	public static <T> Callable<T> getCallable(final String methodName,final Object obj,final Object ... args){
		Callable<T> call = new Callable<T>() {
			@SuppressWarnings("unchecked")
			public T call() throws Exception {
				Method method= obj.getClass().getMethod(methodName, (Class[])null);
				return (T) method.invoke(obj,args);
			}
		};
		return call;
	}
	
	/**
	 * 
	 * @param <T>
	 * @param call
	 * @param timeOut 超时时间
	 * @param unit	时间单位
	 * @return
	 */
	public static <T> T testFuture(Callable<T> call,int timeOut,TimeUnit unit){
		ExecutorService executorService = Executors.newSingleThreadExecutor();
		
		FutureTask<T> futureTask = new FutureTask<T>(call);
		
		executorService.execute(futureTask);
		
		T result = null;
		try {
			result = futureTask.get(timeOut, unit);
		} catch (InterruptedException e) {
			futureTask.cancel(true);
			e.printStackTrace();
		} catch (ExecutionException e) {
			futureTask.cancel(true);
			e.printStackTrace();
		} catch (TimeoutException e) {
			futureTask.cancel(true);
			e.printStackTrace();
		} finally {
			executorService.shutdown();
		}
		
		return result;
	}

 

评论

1 楼 Technoboy 2011-05-25  

引用

result = futureTask.get(timeOut, unit);  

等待1，而线程sleep 5，所以TimeoutException，catch住后

引用

futureTask.cancel(true);  

导致线程InterruptedException，
所以TimeoutException，null,InterruptedException